思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
Opens in a new window。关于这个话题，Line官方版本下载提供了深入分析
SourceTargetMean SSIMNotesWarang Citi digit (U+118EC)x-0.095Script digit vs Latin letterMathematical Script o (U+1D4F8)o-0.088Ornate calligraphic flourishesMath Fraktur l (U+1D574)l-0.083Blackletter vs sans-serifMath Fraktur g (U+1D50A)g-0.083Same issue，详情可参考旺商聊官方下载
The sector was just beginning to boom amid post-World War Two economic prosperity, coupled with a growing preference among consumers for take-home drinks over soda fountains.
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